|
|||||||||||||||||||||
|
|||||||||||||||||||||
| |||||||||||||||||||||
Hi Dee, There are 43560 square feet in an acre so the area of your ranch is $43560 \times 3500$ square feet. From the rough sketch you sent me it looks like you want a roughly rectangular ranch with its length about 5 times its width. Suppose the length is $X$ feet then the width is $5X$ feet. The area of the ranch is then $X \times 5X = 5 X^2$ square feet. Thus \[5X^2 = 43560 \times 3500\] and hence \[X = \sqrt{\frac{43560 \times 3500}{5}} \mbox{ feet.}\] My calculator gives $X = 5,522$ feet. There are 5,280 feet in a mile so that's $\large \frac{5522}{5280} \normalsize = 1.04$ miles. Hence your ranch is approximately 1 mile by 5 miles. Penny | |||||||||||||||||||||
|
|||||||||||||||||||||
Math Central is supported by the University of Regina and the Imperial Oil Foundation. |