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 Question from Hari: why is area of a triangle drawn from centre of a circle i.e. radii forming the sides is 1/2 *r^2 sin theta where r is radius

Hi,

I drew a diagram.

The line segment $BD$ is perpendicular to the side $CA$ of the triangle so that $h,$ which is the length of $BD,$ is the height of the triangle. Write $h$ as a function of the angle measure $\theta.$

Penny