



 
Hi John, The assumption is that $\sqrt 6$ is rational and hence can be written as a fraction $\frac{c}{d}$ where $c$ and $d$ are integers. From your knowledge of equivalent fractions you know there is a fraction $\frac{a}{b}$ which is equivalent to $\frac{c}{d}$ where $a$ and $b$ have no common factors. Hence if $\sqrt 6$ is rational than it can be written as $\frac{a}{b}$ where $a$ and $b$ have no common factors. The remainder of the proof shows from this assumption you can prove that $a$ and $b$ do have a common factor. Hence the assumption that $\sqrt 6$ is rational must be false. I hope this helps,  


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