



 
Hi Joshua, Suppose the domain of $g$ is $D.$ If $g(x)$ is to exist then it must be that $x$ is in $D.$ But if $f(g(x))$ is also to exist $g(x)$ must be in the domain of $f.$ To be more explicit let $E$ be the set of all $t$ so that there is an $s$ in $D$ so that $t = g(s),$ that is \[E = \left\{t  \exists \; s \in D \mbox{ so that } t = g(s) \right\}.\] The domain of $f(g(x))$ is all $x$ in both $D$ and $E,$ that is \[\mbox{ the domain of f(g(x)) is } D \cap E.\] Penny  


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