|
|||||||||||||||||||||
|
|||||||||||||||||||||
| |||||||||||||||||||||
Hi Katherine, If the cyclist rides at 23.66 miles/hours for 96.87 hours then he would travel \[23.66 \frac{\mbox{miles}}{\mbox{ hours}} \times 96.87 \mbox{ hours} = 23.66 \times 96.87 \mbox{ miles} = 2.292 \mbox{ miles.}\] If his rate reduces by 0.1 miles/hour to 23.56 miles/hour, and the distance remains at 23.66 miles what is the time to make the equation above true? Penny | |||||||||||||||||||||
|
|||||||||||||||||||||
Math Central is supported by the University of Regina and the Imperial Oil Foundation. |