



 
Hi Mandy, I drew a graph of $y = 4x  5x^2 = x(4  5x)$ and a line through the origin that looks like it divides the area between the graph and the Xaxis in half. This line intersects the graph at the origin and Q which has coordinates $(a,b).$ This line then has slope $\large \frac{b}{a}.$ I would first integrate $ y = 4x  5x^2$ from $0$ to $P$ to find the area between the graph and the Xaxis. Call this area $B.$ Next find the area shaded green in the diagram, again by integration. Set this area equal to $\large \frac{B}{2}$ and solve for $a.$ Write back if you need more assistance,  


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