|
|||||||||||||||||||||
|
|||||||||||||||||||||
| |||||||||||||||||||||
Hi Patti: I can show you one approach. You could make the $\$5.10$ entirely in nickels but that would be 110 coins, far too many. Maybe it's better to start by maximizing the number of quarters rather than nickels. You can make $\$5.00$ with 20 quarters and then the remaining $\$0.10$ with one dime or two nickels but in either case it is too few coins. To increase the number of coins trade in one quarter for 2 dimes and 1 nickel. Thus you have made $\$5.00$ with 22 coins. If you convert the 2 dimes to 4 nickels and make the remaining $\$0.10$ out of nickels but that is still too few coins. Next I would try 18 quarters. I hope this helps, | |||||||||||||||||||||
|
|||||||||||||||||||||
Math Central is supported by the University of Regina and the Imperial Oil Foundation. |