



 
Hi Alena, I would start by adding (2kx  3k) to each side and then adding (2x + 4) to each side to obtain \[(2x + 4) < kx + 3k\] or \[(2x + 4) < k(x + 3).\] If you are solving for $k$ then you could divide each side by $x + 3$ keeping in mind that is $x + 3 > 0$ then the direction of the inequality remains unchanged and is $x + 3 < 0$ then the direction of the inequality is reversed. But you are looking for the case where there is no solution. What value of $x$ gives no solution? Penny  


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