



 
Hi, I think you are to find the value of $b.$ I would rather work with exponential expressions than with logarithms so I am going to use \[\log_3(a6) = 2b \mbox{ is equivalent to } 3^{2b} = a6\] and \[\log_2(a7) = 3b \mbox{ is equivalent to } 2^{3b} = a7\] Hence you have \[9^b = a6 \mbox{ and } 8^b = a7\] Can you complete it now?




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