



 
Hi Maddie, Suppose that the original price is $\$x$ per dozen and at that price you bought $y$ dozen. You paid $\$6$ so you know that \[x y = 6.\] Ten cents is $\large \frac{1}{10} \mbox {dollars}\] so the increased price is $x + \large \frac{1}{10}$ dollars. At this price you buy $y  2$ dozen for $\$6.$ Hence \[\left( x + \frac{1}{10} \right) \left( y  2 \right) = 6.\] Solve the first equation for $y,$ substitute into the second equation and solve for $x.$ Write back if you need further assistance. Penny
 


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