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Hi, The revenue each month is the rent charged per unit times the number of units rented. Suppose the monthly increase per unit is $RMx,$ then each unit pays $RM(400 + x).$ For each RM10 increase in rent there are 2 vacancies. Hence if the rent increases by $RMx$ there are $2\times \large \frac{x}{10}$ vacancies and hence the number of units rented is $100 - 2\times \large \frac{x}{10}.$ Now use the calculus you know to determine the value of $x$ that will maximize the monthly revenue. Penny |
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