|
||||||||||||
|
||||||||||||
| ||||||||||||
Hi Barbara, Under the hypothesis that the dice are fair construct a table similar to what I created in my response to Jose but rather than recording the sum of the numbers on the two dice, record the difference. If the dice are fair then the probability of landing in each of the 36 cells is $\large \frac{1}{36}.$ Hence you can calculate the probabilities of obtaining a 0, 1, 2, 3, 4, and 5 and hence the expected number of 0s, 1s, up to 5s in 100 rolls. With these expected numbers and observed frequencies you can construct a goodness-of-fit test. Write back if you need more assistance, |
||||||||||||
|
||||||||||||
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |