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 Question from Brandon: Need a formula to find missing large Dia of a truncated cone where the small dia =.19" Height= 2" and taper =16deg

Hi Brandon,

I drew a diagram of what I see from your description.

Since the angle $BDA$ is a right angle

$\tan(16^o) = \frac{x}{2} \mbox{ and hence } x = 2 \times \tan(16^o) = 2 \times 0.2867 = 0.5735.$

Hence the diameter of the circular base of my truncated cone is $0.19 + 2 \times 0.5735 = 1.34$ inches.

I hope this helps,
Harley

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