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Question from Dadzie:

x+s=8→1
y+x=13→2
y-p=6→3
s+p=8→4

Hi,

Since $x + s = 8$ and $y + x = 13$ we know that

\[ (x + s) - (y + x) = 8 - 13.\]

Simplifying gives

\[s - y = -5.\]

What can you do with equations 3 and 4 to get another equation involving only $s$ and $y?$

Penny

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