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 Question from Dadzie: x+s=8→1 y+x=13→2 y-p=6→3 s+p=8→4

Hi,

Since $x + s = 8$ and $y + x = 13$ we know that

$(x + s) - (y + x) = 8 - 13.$

Simplifying gives

$s - y = -5.$

What can you do with equations 3 and 4 to get another equation involving only $s$ and $y?$

Penny

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