



 
Hi Deepak, The first thing I would do is eliminate the fractions in the first equation. Multiply both des of \[\frac{8}{x}  \frac{10}{y} = 1\] by $xy$ to get \[xy \times \frac{8}{x}  xy \times \frac{10}{y} = xy \mbox{ or } 8y  10x = xy.\] Now solve the second equation, $x + y = 9$ for $y$ and substitute into $8y  10x = xy.$ This will give you a quadratic in $x$ which you can solve. Once you have solved for $x$ and $y$ substitute into the original equations to verify your answer. Penny 



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