



 
Hi Patrick, I am going to solve a similar problem.
Suppose the two numbers are $x$ and $y,$ where $y$ is the larger. Since the difference is 3 you know that \[y  x = 3.\] Since the larger number is 5/4 of the smaller you also know that \[y = \frac{5}{4} \times x.\] Substitute this equation into the first equation to get \[\frac{5}{4} x  x = 3.\] Thus \[\frac{1}{4} x = 3 \mbox{ or } x = 12.\] The larger number is 3 more than 12 so $y = 15.$ Now try your problem. Penny 



Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. 