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Question from Will:

-2/3 to the -6 power

Hi Will,

A negative power has a special meaning. If $n$ and $k$ are both numbers then

\[k^{-n} = \left( \frac{1}{k}\right)^{n}.\]

For example

\[6^{-2} = \left(\frac{1}{6}\right)^2 = \frac{1^2}{6^2} = \frac{1}{36}.\]

In your example

\[\left(\frac{-2}{3}\right)^{-6} = \left(\frac{1}{\frac{-2}{3}}\right)^{6}.\]

Can you simplify this expression?

Write back if you need more assistance,
Penny

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