



 
Promise, I am going to illustrate the procedure by dividing 2252 by 23 in base 7 Before I actually start the division I am going to calculate 1× 23_{7}, 2 × 23_{7}, 3× 23_{7} 4× 23_{7} 5× 23_{7} and
and so on. My resulting table is
Now I can start the division. I can see from my multiplication that 23_{7} divides 225_{7} 6 times. Thus I get, after subtraction Again using of the table I see that 23_{7} divides 212_{7} 6 times and thus Hence 2252_{7} divided by 23_{7} is 66_{7} with a remainder of 5_{7} . Penny 



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