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| Math Central | Quandaries & Queries |
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Question from Yesenia: Carmen, Austin, and Trey have a total of $\$128$ in their wallets. Trey has $\$10$ more than Carmen. Austin has 4 times what Trey has. How much do they have in their wallets? |
Hi Yesenia,
I would let $C$ be the amount of money Carmen has in her wallet in dollars, $A$ be the amount of money Austin has in his wallet in dollars, and $T$ be the amount of money Austin has in his wallet in dollars.
You know three facts
- They have a total of $\$128$ in their wallets. This gives the equation
$C + A + T = 128.$
- Trey has $\$10$ more than Carmen. Write this fact as an equation.
- Austin has 4 times what Trey has. Write this fact as an equation.
You now have three equations in the variables $C, A$ and $T.$ Solve these equations for $C, A$ and $T.$
Penny
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