This problem is a calculus 1 limit problem-high school level. I'm teaching myself calc over the summer and I'm already stumped.
find the limit
lim sec^(2)[(sqrt2)(p)]-1 p-->0 --------------------- 1-sec^(2)[(sqrt3)(p)]I'm Ann.
As with many limits involving trigonometry you need to use the fact that
For your problem
Now as p approaches 0 the first two terms approach 1 and the limit can be evaluated.
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