Date: Tue, 27 Oct 1998 09:24:43 EST To: QandQ@MathCentral.uregina.ca Subject: help
We are trying to solve what SHOULD BE a simple 7th grade problem and have run into a wall. It is an addition problem. Each particular letter represents the same digit. We are looking for what number "B" represents. We have tried a multitude of solutions and have come up empty.
Can you help.
Hi Bruce
The sum of 4 D's has a remainder of A when divided by 10 but and A is 1 or 2. But 1 does not appear in the remainder row in the table above so A must be 2. Since A=2 the sum of four A's is 8 and E is a one digit number, the carry from the column of B's must be 0 or 1. Thus B cannot be larger than 4.
- B cannot be 4 as the sum of four 4's sum 16 and a carry of 8 would be required.
- B cannot be 2 as A is 2.
- B cannot be 1 as the sum of four 1's sum 4 and a carry of 7 would be required.
- If B=0 then E=8. An examination of the C's and D's columns shows that this choice for B is also impossible.
What remains now is to show that there is a choice for C and D that solves the puzzle.
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