Secondary question from student.

I need to know:

There is one function with the domain of all real numbers that is both even and odd. Please give me the answer to this question before I go insane.

Thanks,
Kent

Hi Kent

A function f is even if for every x in its domain f(x) = f(-x)
A function f is odd if for every x in its domain f(x) = -f(-x)

Thus a function f is both even and odd if for every x in its domain

So, whatever f(-x) is, it has the property that

the only number a that satisfies a = -a is zero and thus f(x) = 0 for all x.

Cheers
Penny