Date: Fri, 7 May 1999 10:21:52 -0600 (CST)
Subject: Math 12

Who is asking: Student
Level: Secondary

I don't understand how to do this type of question:

log(base absolute value x)y = log(base abs.val.x)2 + log(base abs.val.x)(Cos x)

How do you graph the equation also, if -2(3.14)<=x<=2(3.14)

Thanks for your help!


You didn't give any instructions for the first part of the problem. I am assuming that you are to solve for y or maybe just simplify.

Since log(ab) = log(a) + log(b),

log|x|(y)=log|x|(2) + log|x|(Cos x)
 =log|x|(2 Cos x)

Also the log function is one-to-one so it follows that

y = 2 Cos(x)

Now you should be able to graph the equation.



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