Question:
I am looking for any intecepts. How do I solve: y=x^2 square root of (9-x^2)

Hi Sally

The x-intercepts occur where y=0 and the y-intercepts where x=0. Your expression is

and hence substituting x=0 gives you y=0. Thus the only y-intercept is at (0,0).

To find the x-intercepts set y=0 to get

The left side of this expression is the product of two numbers, x² and the square root of (9-x²). If this product is 0 then either x² is 0 or the square root of (9-x²) is 0. Hence the x-interceps occur at points where either x²=0 or

Cheers
Harley