Subject: word problems, algebra 1
Date: Thu, 4 Feb 1999 21:47:37 -0600
Please answer these problems with a formula. Also explain in English step by step how these problems should be solved. I know the answer I just don't know how the answer was achieved Thank you very much for trying to help
For your first problem you need to realize that, for each trip, you are dealing with 3 things: distance, rate, time. The relationship among them is that distance = rate x time. Decide what you are trying to determine and what relevant information you have. In this case we know the rate up and the rate down, the combined time and the fact that the distance up = the distance down.
Let's do some preliminary thinking. For the up trip we know that distup = 120 x timeup For the down trip we know that distdown = 2640 x timedown We also know that timeup + timedown = 20
Since distup = distdown we know that 120 x tup = 2640 x tdown
To write this concisely let the time up be represented by
c minutes, and the time down be represented by b minutes then
You can divide both sides of the 1st equation by 120 and you find that
Replacing c by 22 b in the second equation gives
So the distance down can be obtained by multiplying this by the speed down.
Problem 2 can be solved in a similar fashion.
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