Date: Wed, 07 Apr 1999 18:56:32 -0700 Sender: Ron Subject: grade 10 math the type of question i'm having trouble with is 5(2x-1)=3(x-4) Hi Ron I am assuming that the instructions are to solve for x. That is find the value of x that makes the equation 5(2x-1) = 3(x-4) a true statement. The procedure is to start with the equation 5(2x-1) = 3(x-4), write a sequence of equivalent algebraic sentences and end with a sentance of the form x = a number. The first step here is to expand both sides of the equation. The right side is 3(x-4) which is equivalent to 3x -3(4) or 3x - 12. Similarly the left side is 5(2x-1) which is equivalent to 5(2x) - 5(1) or 10x - 5. Thus I have 5(2x-1) = 3(x-4) and thus 10x - 5 = 3x - 12 Since the goal equation has only an x on the left of the equal sign the next step is to remove the -5 from this side. This you can do by adding 5 to each side of the equation since this rertains the equality. Thus the next step is hence 10x - 5 + 5= 3x - 12+ 5 or 10x = 3x - 7 Again, since the goal equation has no x on the left side remove the 3x by subtracting 3x from both sides. Thus 10x - 3x= 3x - 7- 3x or 7x = - 7 If you now divide both sides by 7 you get  x = -1 So here is my solution  5(2x-1) = 3(x-4) and thus 10x - 5 = 3x - 12 hence 10x - 5 + 5= 3x - 12+ 5 or 10x = 3x - 7 Thus 10x - 3x= 3x - 7- 3x or 7x = - 7 and therefore x = -1 You can now check that the solution is correct by substituting x = -1 into the original equation to see if the two sides are equal. Cheers Penny Go to Math Central To return to the previous page use your browser's back button.