Date: Sun, 7 Mar 1999 15:42:55 -0600 (CST) To: QandQ@MathCentral.uregina.ca Sender: sivad@canada.com (LSivad) Subject: factoring a differance of a trimonimal square Name: LSivad
Who is asking: Student
Question:
Hi, ^{2} + 6m + 9and I try to factor it. Factoring gives me ^{2} + 6m + 9 = (m + 3)^{2}Thus ^{2}+6m+9-n^{2} = (m + 3)^{2} - n^{2}The pattern I see here is ^{2} - b^{2}which factors as ^{2} - b^{2}=(a - b)(a + b).Thus ^{2}+6m+9-n^{2} = (m + 3)^{2} - n^{2} = (m + 3 - n)(m + 3 + n)Cheers Penny To return to the previous page use your browser's back button. |