Hi there,

My name is Damon. I am a Sask correspondence student and I have a secondary level 12 question that I can't seem to figure out.

It is as follows:

n! = 42(n-2)!

Could you please explain to me how to reach the answer. Thank you in advance for you assistance with this problem.

Yours aye,


Hi Damon,

so, dividing both sides of the equation in question by (n-2)! gives
Expand and rearrange to get n2-n-42=0

Now factor and solve for n. You will find two values for n. Check to see if they are solutions to the original problem.

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