Name: Krista Bischoff Who is asking: Student
Question: I can't get the picture to copy to this form so I guess I will have to try and describe the picture the best that I can. The top right hand corner is folded to the left side, almost half way down. The width of the paper is a ( the width of the bottom part which is not folded.) The creased side is L and the part shorter part of the folded area is x (the part that would have been the top right of the original piece.) I hope that this is good enough for you to understand. Hi Krista,In the diagram below the point P is folded to the point S leaving the "crease" QT of length L. PS is the line segment joing P and S.
Triangles PQU and QSU are congruent and thus angle QUP = angle SUQ. Since their sum is 180^{o} they are each 90^{o} angles. If angle QPU = angle USQ = a then angle PQU =angle UQS = 90^{o}  a. Therefore angle SQR = 2a. Using triangle SQR we see that Using the fact that we see that Also from triangle PQT Thus
Cheers,
