Subject: Calculus

Name: Jeff Ellis
Who is asking: Teacher
Level: Secondary

Question: If F(x)=(4+x)(3+2x2)2(2+3x3)3, find F'(0)

I have attempted it but I am not sure if my answer is right. Thanks for the help.

Hi Jeff,

If

F(x)=(4+x)(3+2x2)2(2+3x3)3

Then

F'(x) =   1[(3+2x2)2(2+3x3)3]
  + (4+x)d/dx[(3+2x2)2(2+3x3)3]
  =   1[(3+2x2)2(2+3x3)3]
  + (4+x)[2(3+2x2)(4x)(2+3x3)3 + (3+2x2)23(2+3x3)2(9x2)]

Thus

 F'(0)= 1[(3+0)2(2+0)3]
  + (4+0)[2(3+0)(0)(2+0)3 + (3+0)23(2+0)2(0)]
  = 32 23 = 72
Cheers,
Harley
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