Name: leslie Who is asking: Student Level: Secondary Question: add 4x+1 3x+2 49x+4 over + over + over x8 x+4 x^24x32 6 2x solve x over = over x3 x3Hi Leslie, Working with algebraic fractions is very similar to working woth arithmetic fractions. To add fractions they need the same denominator. You have denominators x8, x+4 and x^{2}4x+32. But x^{2}4x+32 = (x8)(x+4) so if you multiply the numerator and denomonator of the first fraction by x+4 and the numerator and denomonator of the second fraction by x8 then all three fractions will have the same denominator. That is For your second problem I would multiply both sides by x3 and then solve. Thus Solve this equation for x and then verify by substituting into the original equation. Cheers,Penny
