Subject: studdent from Australia, yr 12 (final year) hello. i am kylie mcalpine and a final year student in Perth, western australia. i was told about this webstie so i decided to ask for your assistance in and investigation i am currently doing at school there are 3 tables
the other 2 tables included are n to the power of 7, n being 110 and the other is 4 to the power of n i have figured out the patterns for the tables, the last digits in the table of 3 forms a continuos pattern of 3,9,1,7 the other tables have patterns as well. table 7 has the pattern of 7,,9,3,1 and table 4 has the pattern of 4,6,4,6 etc. the questions we have been asked are what is the units digit of the following:
a) 3^{58} and the harder question of: what is the units digit of the following sum: 13^{841} + 17^{508} + 24^{617} = ??????? if there is any information i have not included, please inform me. thankyou again
Here is an outline of how to do it:
The pattern repeats every four digits. Imagine that you complete this table to 58 rows. 58/4 = 14 with a REMAINDER 2 so the pattern repeats 14 times and then there are two more rows with 3 and 9 in the units digit column. Thus the units digit of 3^{58} is 9. Using the same technique you can complete the next two problems. For the harder question use the above technique to find the units digit of each of 13^{841}, 17^{508} and 24^{617}. Cheers,Paul and Penny
