My name is Monica I am a 12th grade student. My problem is in geometry.
Given: ABCD is a square; AX is perpendicular to BY Label the point of intersection of AX and BY as P, as in the diagram below. Since triangle ABP is a right angle triangle, and the three angles in any triangle sum to 180^{o}, angle ABP + angle 1 = 90^{o}. Since angle ABX is a right angle, angle ABP + angle 3 = 90^{o}. Thus angle 1 = angle 3. Cheers,Chris
