Subject: indefinite integral

I am to find the indefinite integral of: (ex - e-x)2 dx

I know that I rename u for 2x and solve for dx by using the derivative of 2x. Then substitute "u" and the formula "dx" into the orginial formula and apply the approiate rule, then subtiute back what "u" held the place for. Once I do this I should be able to take the derivative to check my answer. Do you have in suggestions.

Bonnie Null

Hi Bonnie,

Try expanding (ex - e-x)2 using (A - B)2 = A2 - 2AB + B2 and then applying the substitution u = 2x.

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