Name: Catherine Sullivan Question: Please help me with the following: The radioactive isotope carbon-14 is present in small quantities in all life forms, and it is constantly replenished until the organism dies, after which it decays to carbon-12 at a rate proportional to the amount of C-14 present, with a half life of 5730 years. Suppose C(t) is the amount of C-14 at time t.
Note: for part 1, I know how to solve for k using the equation C=C*ekt, but I need to do it from the differential equation. I took the integral of both sides but was left with a first derivative and too many unknowns. Please help!! Thanks Hi Catherine,C is the amount of carbon-14 that is present at time t. (Sometimes it helps to write C(t) to emphasize that it is a function of t.) Start with the differential equation C' = -k C and divide both sides by C to get Integrate both sides with respect to t and the equation becomes Integration produces where H is a constant. Now solve for C by taking the expontanial of each side and you get where A is the constant eH. Thus you have the equation C = A e-k t which you can solve for k. Cheers,Harley
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