Math Central - mathcentral.uregina.ca
Quandaries & Queries
Q & Q
 Topic: compound proporations
start over

One item is filed under this topic.

 Page1/1
 4 carpenters can build 8 houses in 10 days. 2016-04-05 From Kenneth:Hello: Here is my question: 4 carpenters can build 8 houses in 10 days. 2 carpenters can build how many houses in 15 days? Here is one solution: The number of houses built is jointly proportional to the number of carpenters and the number of days. So h = kcd where k is a constant. Substituting the given: 8 = k*40, so k = 1/5. Our formula is then h = cd/5. I'm not sure how to determine whether or not one unit is jointly proportional to any other unit. However, if 2 carpenters are unknown as in 4 carpenters can build 8 houses in 10 days. How many carpenters can build 6 houses in 15 days? What is the solution using this method? And likewise, if days are unknown, as in 4 carpenters can build 8 houses in 10 days. 2 carpenters can build 6 houses in how many days? I thank you for your assistance.Answered by Penny Nom.

 Page1/1

 Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.
 about math central :: site map :: links :: notre site français