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Quandaries & Queries
Q & Q
 Topic: quotient rule
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 Concavity and the second derivative 2008-10-15 From Christina:I'm having trouble solving for a second derivative for the following graphing question. f(x) = (X^2+2x+4)/2x using the quotient rule, I found: f'(x) = (x^2-4)/(2x^2) however, using the quotient rule again I can't seem to solve it (concavity): f'''(x)=[(2x)(2x^2)-(x^2-4)(4x)]/[(2x^2)^2] f''(x)=[(4x^3-(4x^3 -16x)]/4x^4 f''(x)=16x/4x^4 f''(x)=4/x^3 and making the equation equal to zero result in 0=4 which doesn't seem to make sense...Answered by Penny Nom. The quotient rule 2000-02-21 From Charlene Anderson:Question: I came across a question in our book that states: Let Q(x) = N(x) / D(x) Then re-write Q(x) in a form that can utilize the Power and Product Rules. Use this rearranged form to derive the Quotient Rule. The Quotient Rule can be derived from the Power Rule and the Product Rule. One must also use the chain rule too, right? Answered by Harley Weston.

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