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Hi Megan, Draw a coordinate system on the plane with the x-axis at ground level and the y-axis the axis of symmetry of the parabola. The width of the bridge is 192 feet so the parabola crosses the x-axis with x-coordinates ± 192/2 = ± 96. The maximum height occurs at x = 0 so the vertex of the parabola is (0, 30). Since the curve is a parabola which opens downward its equation can be written f(x) = ax2 + bx + c.
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Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences. |