From Irena: In transferring 1260J of heat to water, the temperature of 0.20 kg of mercury falls 50 K. Calculate the specific heat capacity of mercury using the equation C= Q/(m)(delta t)
i know that Q= -1260J because it's loosing heat and m= 0.2kg and since i have to use 'C i have to convert Kelvins into Celsius (i also know that 'C has to be negative since it looses heat) . . .
Answered by Harley Weston.
Page 1/1
Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.
