6 items are filed under this topic.
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An equivalence relation |
2009-04-22 |
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From syed:
D is the relation defined on Z as follows:
Z is an integer
For all m,n E Z, m D n if and only if 3 l (m^2 - n^2).
Find out whether the above relation satisfies to reflexive , Symmetric & transitive?
Is it an equivalence?
Answered by Robert Dawson. |
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An equivalence relation |
2008-08-27 |
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From Francesca:
In this problem we are told to find out if the given set is an equivalence relation or not.
{(x,y) such that 4 divides x-y}. What I am confused about is whether or not for instance if I picked (1,5) as a part of the set whether I could put in (5,1) as well or whether that would be wrong. Thanks!
Answered by Victoria West. |
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Equivalence relation |
2008-03-19 |
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From Hmod:
State with reasons, whether the relation R on N X N given by mRn
if m and n have difefrent remainders on division by 2 is an Equivalence
relation
Answered by Victoria West. |
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Equivalence relations |
2007-07-18 |
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From jim:
Determine whether the given relation is an equivalence relation on the set. Describe the partition arising from each equivalence relations.
1. x is Related to y in Real number if lxl=lyl.
2. n is Related to m in Z+ if n and m have the same number of digits in the usual base ten notation.
Let n be a particular integer in Z+. Show that congruence modulo n is
an equivalence relation on Z.
Answered by Harley Weston. |
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Equivalence relations on a set of cardinality n |
2002-07-06 |
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From Siddhartha:
what is the no. of equivalence and transitive relations on a set of cardinality n?
Answered by Penny Nom. |
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Equivalence Relations |
1999-05-06 |
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From Megan:
I am tutoring a boy who got this assignment from his teacher and I have no clue how to do it because I don't even know what the questions is asking! I need some help. Hereit is: "Give five examples of relations which are not equivalent relations and five examples of equivalent relations and explain why they are equivalent relations." This is seventh grade and I read about it in his book but it is not coming together for me.
Answered by Chris Fisher. |
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