 |
From Jay:
I've seen solution methods for finding the last 2 digits
of a^k = N, where a and k are known. My question
is:
What if the number N is known and the last 2
digits are, say, ...62. Is there a way to find, for
any given a, the value of k which will result in a
number where the last 2 digits are ...62? and if
that is possible, then do the same for
a number with the last n digits (say 7 or 53 or
something)?
Answered by Harley Weston. |
