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One item is filed under this topic.
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Simson line |
2013-05-23 |
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From Nazrul:
From any point p lying on the circumcircle of the triangle perpendiculars
PD , PE are drawn on BC,CA respectively. The line segment ED intersects at
the point 0 ; prove that PO ⊥ AB ( PO is perpendicular to AB ).
Answered by Chris Fisher. |
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