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2 items are filed under this topic.
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More on the sixth degree equation |
2007-08-21 |
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From Farzan:
Equation 1 :
(R + (6.67*5.98*10^13/((R^2)*2)))^2 - (R^2) = (7.27*(10^-5)*R)^2
Equation 2 :
(6.67*5.98*10^13/(R^2*2))^2 + 6.67*5.98*10^13/R = (7.27*10^-5*R)^2
As you see if we expand the left part of the first equation and simplify, the
equations become same, but these two equations have different answers in my
math software.The first one has 3 amounts for R, but the second one has 6
amounts. Why are the answers different ?
Answered by Stephen La Rocque. |
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A sixth degree equation |
2007-08-20 |
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From Farzan:
Dear friends
I need to solve this equation with an understandable method for high-school students :
(6.67*5.98*10^13/(R^2*2))^2 + 6.67*5.98*10^13/R = (7.27*10^-5*R)^2
please solve this problem if you have time.
Answered by Harley Weston. |
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