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One item is filed under this topic.
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A problem involving squarefree integers |
2007-05-07 |
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From Andrew:
I was told that if x > y (integers); then x would never exactly =
divide y^n (n integer > 1) if (x,y) =3D 1 ; or if x is "square =
free". Is the latter true and why?
Answered by Stephen La Rocque and Penny Nom. |
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