



 
Hi Mary, On my rough sketch of your property I added a diagonal to subdivide the property into two triangles. Since the angle at C is a right angle the area of triangle DBC is
To find the area of triangle ABD I need to find the length of the diagonal BD which I can do using Pythagoras' Theorem on the right triangle DBC.
Now that I know the lengths of all three sides of triangle ABD I can use Heron's Formula to find its area. I got the area of triangle ABD to be 602.049 square metres. Thus the area of your property is 371.662 + 602.049 = 973.711 square metres. If you really want the area in square feet you can ask Google to make the conversion. Type the phrase
into the Google search engine and it returns
Harley  


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