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Question from x, a student:

a box consists of 10 light bulbs inspected by the following procedure: 2 bulbs are chosen at random without replacement. the box is only accepted if both bulbs work. suppose that the box contains 1 defective bulb. what is the probability of accepting the box?

Hi,

The number of ways of choosing 2 bulbs from 10 bulbs is 10 choose 2. The number of outcomes that will result in accepting the box is the number of ways of choosing 2 bulbs from the 9 non-defective bulbs.

What is the probability of accepting the box?

Penny

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