



 
Aye, In my diagram the blue bar at the bottom marks sea level and the height of the mountain is h m above sea level Triangle AQB is a right triangle, AQ = 950  875 = 75 m and AB = 2400 m. Thus you can use Pythagoras' theorem to find the distance x = QB. Now your situation is very similar to the problem we received from Brina a while ago. You can proceed as Stephen did to solve Brina's problem using triangles TRA and TPB. In Stephen's solution the two triangles had the same height but in your problem the triangles have heights h  RS m and h  PS m respectively. But you know RS and PS so Stephen's technique should work for you. Harley  


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