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 Ryan, Are the zeros 1, -1 and i where i is the square root of -1? Also you have said that f(x) = 160 and I think the "x" should be some specific number. Can you check this and get back to us? Penny Ryan replied 
 Ryan, I don't understand but let's proceed as if the zeros are 1, -1 and i = √-1. TOne fact you need is that if a polynomial with real coefficients has a complex zero then the complex conjugate is a zero also. Thus in your situation both i and -i are zeros of the polynomial. Now look at Harley's response to a question from Kristen and see if that helps with your problem. Write back if you need more assistance,  | ||||||||||||
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