SEARCH HOME
Math CentralQuandaries & Queries

search

Question from Ryan, a student:

What is the fourth degree polynomial function with real coefficients
that has -1,1 and I as zeros and such that f(x)=160

Ryan,

Are the zeros 1, -1 and i where i is the square root of -1? Also you have said that f(x) = 160 and I think the "x" should be some specific number. Can you check this and get back to us?

Penny

Ryan replied

I believe the correct answer is x=(160 .5+1) .5
I cannot properly express in email without symbols. But I am assuming you understand.

Ryan,

I don't understand but let's proceed as if the zeros are 1, -1 and i = √-1.

TOne fact you need is that if a polynomial with real coefficients has a complex zero then the complex conjugate is a zero also. Thus in your situation both i and -i are zeros of the polynomial.

Now look at Harley's response to a question from Kristen and see if that helps with your problem.

Write back if you need more assistance,
Penny

About Math Central
 

 


Math Central is supported by the University of Regina and The Pacific Institute for the Mathematical Sciences.
Quandaries & Queries page Home page University of Regina PIMS