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Peter, Not perfectly. Let's think about what happens with the four players who are in group 1 on the first day. If all four of them are in groups 2, 3 and 4 on any other day, then two of them must be in the same group (again). The same is true for the players in groups 2, 3 and 4. So no matter what you do, if no pair is together twice then on each day there at least 4 players who are in the same group number as a previous day. --Victoria | ||||||||||||
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