



 
Hi Victoria, If you join each of the vertices of the pentagon to the center $C$ of the circle you will see that the pentagon is partitioned into five congruent isosceles triangles. I have labeled one of these triangles $ABC.$ Thus the area of the pentagon is 5 times the area of the triangle $ABC.$ S\Also you can see that the measure of the angle $BCA$ is $\frac{360^o}{5} = 72^{o}.$ You can use the technique in my response to a question by Sela to find the area of triangle $ABC.$ Penny  


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